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He equation for the circle is: x2+y2−12x+6y−19=0 . What is the center of the circle?
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He equation for the circle is: x2+y2−12x+6y−19=0 . What is the center of the circle?

User Paul Gerarts
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1 Answer

3 votes

Answer:

Confirming that (6,-3) is correct.

Explanation:

User Timhaak
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