Question

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Answer 1

Let's check your answer:

`\begin{gathered} f(x)=3(6^{\text{ -x}}) \\ f(1)=3(6^{\text{ -1}})=3((1)/(6))=(3)/(6)=(1)/(2) \\ \\ f(2)=3(6^{\text{ -2}})=3((1)/(6^2))=3((1)/(36))\text{ = }(1)/(12) \\ \\ f(3)=3(6^{\text{ -3}})=3((1)/(6^3))=3((1)/(216))=(3)/(216)=(1)/(72) \\ \end{gathered}`

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