Question

In a hydroelectricity production, water falls from a dam into a turbine wheel 49 m below. What is the velocity of water at the turbine?

Answer 1

Given:

The fall height of the water, h=49 m

To find:

The velocity of the water at the turbine.

Step-by-step explanation:

Let us assume that the initial velocity of the water is u=0 m/s

The water will be falling under the influence of the acceleration of gravity. Thus the acceleration of the water will be g=9.8 m/s².

From the equation of motion,

`v^2=u^2+2gh`

Where v is the velocity of the water at the turbine.

On substituting the known values,

`\begin{gathered} v^2=0+2*9.8*49 \\ \Rightarrow v=\sqrt[]{2*9.8*49} \\ =31\text{ m/s} \end{gathered}`

Step-by-step explanation:

The velocity of the water