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Kyle has three short straws, four medium straws, and six long straws. If he randomly draws two straws, one at a time without replacement, what is the probability that both are short straws?

2 Answers

5 votes

Answer: 1 /26

Step-by-step explanation: To calculate probability of two dependent events you multiply their probabilities together. Remember that without replacement means you have to subtract one from the denominator. Therefore you should multiply 3/ 13 ⋅ 2/ 12 to get the solution 1/ 26 .

User Scrashdemix
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Before the first straw is drawn, there are three short straws and
3+4+6=13 straws in all. Thus, the probability of drawing a short straw first is
(3)/(13).

After a short straw is drawn, there are two short straws and twelve total straws, a probability of
(2)/(12) = (1)/(6).

Thus, the probability of both of these events occurring is
(3)/(13) \cdot (1)/(6) = \boxed{(1)/(26)}.
User Lomec
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