Question

How do you solve for b when the equation is 48/b^2 =750/b^5 ?

Answer 1

First off, you're going to end up with 2 answers.

Alright so you have:


`(48)/(b^2) = (750)/(b^5)`

You'll want to multiply both sides by b²

You'll end up with:


`48 = (750)/(b^3)`

Multiply both sides by
`b^5`

Now you should have:


`48b^5 = 750b^2`

Subtract 750b^2 from both sides.

Now:

`48b^5 - 750b^2 = 0`

Factor the left side of the equation:

`6b^2(2b-5)(4b^2+10b+25)=0`

Set both factors to 0:

`2b - 5 = 0`
`4b^2+10b+25=0`

Your Answers:
b = 0 or b =
`(5)/(2)`

Answer 2