Solve for the molecules present in 1296 g of dinitrogen pentoxide (N2O5)
The molar mass of N2O5 is 108 g/mol.
1296g of N2O5 has 1296 / 108 = 12 moles.
1 mole contains 6.022 x 10^23 molecules.
6.022 x 10^23 x 12 = 7.226 x 10^24
Therefore, there are 7.226 septillion ( 7.226 x 10^24 ) molecules in 1296g of dinitrogen pentoxide.