Rearrange the equation:

Isolate the log on its own

To get rid of the log you must do 10^2.42

Then multiply both sides by (1.5 - x)


Solve normally

Hope that helps. Please send me a message if there's patchy bits. Also I'm sure you'll figure this out, but just in case, anywhere I've put down a 2dp shows that I've rounded the number to 2 decimal places. It becomes a pain to deal with otherwise.