Answer:
23 and 29
Explanation:
We can cross out all the even numbers because they are all multiples of 2 so then we are left with: 21,23,25,27,29
We can use the divisibility rule for 3 which is to add the numbers in the number up and see if it can be divisible to 3
2+1=3
2+3=5
2+5=7
2+7=9
2+9=11
21 and 27 get crossed out
25 will get crossed out because any number that has a 5 or a 0 at the end is divisible by 5.
That leaves us with 23 and 29
They can't be divisible by 9,6,3,2,5,7,8 since the multiples of those numbers in the 20s do not match up with 23 or 29
So 23 and 29 is the answer