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Factor completely 3ab(x + 1) − 2(x + 1)

User Difurious
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2 Answers

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3ab(x + 1) − 2(x + 1)
= (x + 1)(3ab - 2)

hope that helps
User Zavanton
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7 votes

Answer:

The complete factor of
3ab(x+1)-2(x+1) is
\Rightarrow (x+1)(3ab-2)

Explanation:

Given:
3ab(x+1)-2(x+1)

We need to factor completely.

Here we have two term. taking common factor from it.

We can see (x+1) is common in both.


\Rightarrow (x+1)(3ab-2)

Write the rest of term in second parentheses

Hence, The complete factor of
3ab(x+1)-2(x+1) is
\Rightarrow (x+1)(3ab-2)

User Openwld
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8.4k points