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2 votes
Write an equation for the line that is parallel to the given line and passes through the given point

y=5x+10; (2,14)


y = 1/5x+4
y = 5x+4
y = -1/5x - 4
y=5x-68

User Karyn
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2 Answers

5 votes
Y = 5x+4. The slope is the same, 5, making them parallel, and when you plug in 2 for x you get 14
User Sunn
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8.5k points
4 votes

Answer:


y = 5x+4

Explanation:

For this case we have the following equation:


y = 5x +10

And we want a line parallel to this one that passes thourgh the point (2,14). In order to satisfy this we need that condition:


m_1 = m_2 =5

Where
m_1 = 5 on this case for the original slope, and if we solve for
m_2 we got:


m_2 = 5

And now since we have the new slope we can solve for the value of b like this:


14 = 5*(2) + b

And if we solve for b we got:


b = 14- 10= 4

And then our equation parallel is given by:


y = 5x+4

User Parsaria
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