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According to the Fundamental Theorem of Algebra, how many roots exist for the polynomial function? f(x) = (x3 – 3x + 1)2
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According to the Fundamental Theorem of Algebra, how many roots exist for the polynomial function? f(x) = (x3 – 3x + 1)2
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Feb 6, 2018
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According to the Fundamental Theorem of Algebra, how many roots exist for the polynomial function?
f(x) = (x3 – 3x + 1)2
Mathematics
high-school
Jonah Graham
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Jonah Graham
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Answer:
6
Explanation:
Because im from zone 6
RevMoon
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Feb 7, 2018
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RevMoon
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It should have 3 solutions.
The number of solutions depends on the term with the highest exponent.
So, in this case we have a cubic equation, there are 3 solutions.
If we have a quartic equation (4th power), there should be 4 solutions.
Pazams
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Feb 11, 2018
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Pazams
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