Question

He function y=−16x2+v0x models the height of a golf ball in feet x seconds after a player hits it. In the equation of the function, v0 is the initial velocity of the ball in feet per second. The ball returns to the ground 3 seconds after it is hit.

What is the value of ​ v0 ​?

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Answer 1

V0 = 48 feet per second is the answer.

Explanation:

The given function which represents height of a golf ball in feet after x seconds after a player hits it.

y = -16x² + v0x

here v0 is the initial velocity and we have to calculate initial velocity. The ball returns to the ground 3 seconds after it is hit.

After 3 seconds height of the ball will be 0.

Now from the given function

0 = -16(3)² + v0×3

3v = 16×9

v0 = 16×9/3 = 48 feet per second.