Question

The quantity of soda consumed per week at a soda fountain is 34 liters, with a standard deviation of 5.8 liters. If any 80 weeks were sampled randomly, what would be the margin of error of the sample mean?

Answer 1

5.8/ sqrt 80=0.648 I think you are asking for the standard margin
Hope this works

Answer 2

The margin of error of the sample mean is 0.648.

Explanation:

The standard error(margin of error) of a sample mean is given by the following formula:

`SE = (s)/(√(n))`

In which s is the standard deviation of the sample and n is the size of the sample.

In this problem, we have that:

`s = 5.8, n = 80`

So

`SE = (5.8)/(√(80)) = 0.648`

The margin of error of the sample mean is 0.648.