Question

May someone pls help me . & at least try to show a little bit of work . Thank you * * ++:(%*=+!!

Answer 1

Let's call x the width of the rectangle and y the length of the rectangle.

The width of the rectangle is 12 less than the length, so:

x = y - 12 equation 1

Also, the perimeter is 156 inches, so:

2x + 2y = 156 equation 2

Replacing equation 1 on equation 2, and solving for y, we get:

`\begin{gathered} 2(y-12)+2y=156 \\ 2y-24+2y=156 \\ 4y\text{ -24=156} \end{gathered}`
`\begin{gathered} 4y-24+24=156+24 \\ 4y=180 \\ (4y)/(4)=(180)/(4) \\ y=45 \end{gathered}`

Then, replacing the value of y on the first equation, we get:

x = 45 - 12

x = 33

Finally, the width is 33 and the length is 45 inches.