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Which linear inequality could represent the given table of values?

y < –2x + 3
y ≤ –2x + 3
y > –x – 3
y ≤ –x – 3

Which linear inequality could represent the given table of values? y < –2x + 3 y-example-1
User Martynas
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2 Answers

6 votes

Answer:

b

Explanation:

User Pavel Gruba
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Answer: The answer is (B) y ≤ –2x + 3 .

Step-by-step explanation: We are to select the correct linear inequality that could represent the table of values given in the question.

If (x, y) = (-4, -1), then


y=-1,\\\\-2x+3=-2*(-4)+3=8+3=11.

So, y < -2x + 3.

If (x, y) = (-2, 4), then


y=4,\\\\-2x+3=-2*(-2)+3=4+3=7.

So, y < -2x + 3.

If (x, y) = (3, -3), then


y=-3,\\\\-2x+3=-2* 3+3=-6+3=-3.

So, y = -2x + 3.

If (x, y) = (3, -4), then


y=-4,\\\\-2x+3=-2* 3+3=-6+3=-3.

So, y < -2x + 3.

Therefore, we have y is either less than or equal to (-2x + 3).

Thus, y ≤ –2x + 3 and (B) is the correct option.

User Andre Borges
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