Question

How many milliliters of 2.00 m h2so4 are needed to provide 0.250 mole of h2so4?

Answer 1

125 ml of 2.00 M solution of sulfuric acid will give 0.250 moles of sulfuric acid.

Step-by-step explanation:

`Molarity=\frac{\text{Mass of compound}}{\text{Molar mass of compound}* \text{volume of solution (L)}}=\frac{\text{Moles of compound}}{\text{Volume of the solution} (L)}`

Volume of the sulfuric acid solution = V

Moles of sulfuric acid = 0.250 moles

Molarity of the sulfuric acid solution = 2.00 M

`2.00 M=(0.250 moles)/(V)`

V = 0.125 L = 125 mL

125 ml of 2.00 M solution of sulfuric acid will give 0.250 moles of sulfuric acid.

Answer 2

Given: 2.00 m h2so4 / L
0.250 moles
Solve
To get the volume we need to divide 0.250 moles from 2.00 moles / L

Volume = (0.250 moles)
-----------------------
(2.00 moles/L)


= 0.125 L x 100
= 125 ml

So the answer is 125 milliliters of 2.00 m h2so4 are necessary to provide 0.250 mole of it.