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Can you explain to me how to do MCQ number 62?

Can you explain to me how to do MCQ number 62?-example-1
User Florin Ionce
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1 Answer

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So we have two opposing forces all things considered. We have the force of gravity pulling the box down and the force of friction trying to resist the force of gravity.

The force of gravity is mg

but because you are trying to find acceleration in the x component, we use cos (theta) to get the horizontal component

so the force of gravity on the box is mg cos theta

Now on friction

The force of friction is (mu) * normal force

Normal force is mg sin theta because you are trying to get the vertical component of gravity for friction

so mg (mu) sin theta is the downward force

combining what we have

Net Force = mg cos theta - mg (mu) sin theta

Net force = ma, and by dividing out mass,

we get

a = g cos theta - g (mu) sin theta, which simplifies down to a = g (cos theta - mu sin theta)

User Orzechow
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