Question

calculate the value of x where the functiony = f(x) = 1822.8(1.4^x)will predict the transistor value f(x) = 406,500,000,000

Answer 1

Given:

The function is:

`f(x)=1822.8(1.4^x)`

Find-:

Value of "x." when f(x) is 406500000000

Explanation-:

The value of "x" is:

`\begin{gathered} f(x)=1822.8(1.4^x) \\ \\ f(x)=406500000000 \end{gathered}`

The value of "x" is:

`\begin{gathered} 1822.8(1.4)^x=406500000000 \\ \\ 1.4^x=(4065*10^8)/(1822.8) \\ \\ 1.4^x=2.23*10^8 \end{gathered}`

Taking log both sides then,

`\begin{gathered} \log_.1.4^x=\log_.2.23*10^8 \\ \\ x=(\log_.2.23*10^8)/(\log_.1.4) \\ \\ x=(8.348)/(0.146) \\ \\ x=57.13 \end{gathered}`

The value of "x" is 57.13