Question

15) If the temperature of the equilibrium system CH3OH(g) + 101 kJ ➡️⬅️ CO(g) + 2H2(g) increases, KDecreasesIncreaseIncrease or decreasesDoes not change 16) which of the following changes would result in an increase of nitrogen dioxide, NO2?N2O4(g) ➡️⬅️2NO2(g) H°=58kJIncreasing volume Increasing pressure Addition of He(g)Decrease temperature

Answer 1

Step-by-step explanation:

The reaction:

CH3OH(g) + 101 kJ <=> CO(g) + 2H2(g)

101 kJ = heat of the reaction

101 kJ is considered here to be a reactant because it is on the left side of the reaction. (remember: 101 kJ is the heat of the reaction, we will consider it as a reactant to understand the explanation better)

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If the temperature increases, the constant K will increase too and the equilibrium will shift to the right.

This occurs because an endothermic reaction benefits from high temperatures.

Answer: K increases