Question

What is the side of the line tei contains the points

Answer 1

To solve the exercise you can use the slope formula:

`\begin{gathered} m=(y_(2)-y_(1))/(x_(2)-x_(1)) \\ \text{ Where m is the slope and} \\ (x_1,y_1)\text{ and }(x_2,y_2)\text{ are two points through which the line passes} \end{gathered}`

So, in this case, you have

`\begin{gathered} (x_1,y_1)=(-1,2) \\ (x_2,y_2)=(3,3) \end{gathered}`
`\begin{gathered} m=(3-2)/(3-(-1)) \\ m=(1)/(3+1) \\ m=(1)/(4) \end{gathered}`

Therefore, the slope of the line that contains the points (-1,2) and (3,3) is

`(1)/(4)`

and the correct answer is option B.