Question

Consider the segment below.

у
6
Top
Mid
Par
5
E
4
3
2.
Che
1
0
-6-5-4-3-2-1 0 1
X
2 3 4
5
C
-2
-3
F
-4
-5
If H is the midpoint of EF, what is the approximate distance of HF?

Answer 1

The face can be drawn as,

The requried coordintes are,

A(4,10)

B(10,8)

C(8,6)

D(8,-2)

E(4,-6)

F(-2,-6)

G(-8,-4)

H(-6,6)

I(-10,8)

J(-4,10)

K(-2,8)

L(2,8)