First of all you should find the zeros.
(1)You can do this by factoring.
(x²-1)(x²-9)
Now you can factor these because it is the difference of two perfect squares.
(x+1)(x-1)(x+3)(x-3)
x+1=0 ; x-1=0 ; x+3=0 ; x-3=0
x=-1 ; x=1 ; x=-3 ; x=3 (Skip to step 3)
OR
(2)It is a quadratic function because a quadratic function is defined as ax²ⁿ+bxⁿ+c. You can use the quadratic function to find the zeros which is xⁿ=[-b±√(b²-4ac)]/(2a).
Therefore, x²=[-(-10)±√((-10)²-4(1)(9))]/(2(1)).
x²=[10±√(100-36)]/2
x²=(10±√64)/2
x²=(10±8)/2
x²=2/2 or 18/2
x²=1 or 9
x=±√1 or ±√9
x=±1 or ±3
(3)You can graph these zeros on the x-axis as (1,0), (-1,0), (3,0), (-3,0).
(4)Next find the numbers in between the numbers in between the zeros by plugging them into the equation. (-2,-15), (0,9), (2,-15)
This will give you other points on the graph which should all be smooth curves. After all of those points, the function should go in the general direction it is already going because those zeros are the only place it can touch on the x-axis.