Question

What is the area of the shaded region?

(25π – 48) cm2
(25π – 30) cm2
(25π – 24) cm2
(25π – 12) cm2

Answer 1

(25\pi\ -24)\ cm^{2} C

Explanation:

on e2020

Answer 2

`(25\pi\ -24)\ cm^(2)`

Explanation:

we know that

The area of the shaded region is equal to the area of the circle minus the area of the two isosceles triangles

so

Find the area of the circle

The area of the circle is equal to

`A=\pi r^(2)`

where r is the radius of the circle

In this problem we have

`r=5\ cm`

substitute

`A=\pi (5)^(2)`

`A1=25\pi\ cm^(2)`

Find the area of the two triangles

The area of the two isosceles triangles is equal to

`A=2[(1)/(2)bh]=bh`

we have

`b=6\ cm`

`h=5-1=4\ cm`

substitute

`A2=6*4=24\ cm^(2)`

Find the area of the shaded region

`A1-A2=(25\pi\ -24)\ cm^(2)`