Question

A point charge of 8.0 C is placed 0.050 m from a rod that has an electric field of 1.5 × 103 N/C. What is the electric potential energy of the point charge? 6.0 × 10-4 J 2.4 × 10-1 J 6.0 × 102 J 2.4 × 105 J

Answer 1

on edge the answer is 6.0 × 10^-4 J

just took the test

Answer 2

We can solve the equation using the formula for electric potential in the electric of a point charge such as shown below:
V = (K*Q)/D

We are given with some values such as:
K = 1.5 x10^3
Q=8.0 C
D=0.05 meters

Solving for V:
V = (8.0 * 1.5x10^3)/0.05
V = 2.4 x 10^ J