Question

Could someone help me with this please and thank you!!
Will mark and star!!

Answer 1

The rule for expressing a radical as a rational exponent is as follows:

`\sqrt[n]{x^y} = x^ (y)/(n)`
So, to find
`\sqrt[3]{27x^2y^3z^4}` use that rule.
The cube root of 27 is 3, so the equation will start with 3.

`3x^ (2)/(3) yz^ (4)/(3)`
Hope that helps!