Question

april swims 50 m north and then turns and swims 20 m back to the south . What is her velocity if it takes her 60 seconds ?

Answer 1

its .5 north hope  its  helps 

Answer 2

v = 0.5 m/s

Step-by-step explanation:

It is given that ,

Initially april swims 50 meter north so distance travelled by her in north direction
`d_(north)=50\ m`

Then she turns 20 meter south so distance travelled by her in south direction is
`d_(south)=20\ m`

Time taken by her
`t=60\ s`

We need to find the velocity she travelled with.

Therefore, velocity
`v=(displacement\ travelled)/(time\ taken\ to\ travel\ the\ displacement)` equation 1..

We know displacement is given as distance between final position and initial position.

As we know april first move 50 m north from its initial position and came back 20 m south.

So, displacement by april is given is
`d=d_(north)-d_(south)=30 m`

Putting values of displacement covered and time taken in equation 1 ,we get
`v=(30)/(60)=0.5\ m/s`

Hence this is the required solution.