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If f(1) = 160 and f(n + 1) = –2f(n), what is f(4)?
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May 10, 2018
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If f(1) = 160 and f(n + 1) = –2f(n), what is f(4)?
Mathematics
high-school
Azfar
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Azfar
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f(4) = f(3+1) = -2f(3) [Using f(n+1) = -2f(n)]
Keep using f(n+1):
-2f(3) = -2f(2+1) = -2[-2f(2)] = 4f(2)
Again:
4f(2) = 4f(1+1) = 4[-2f(1)] = -8f(1) = -8*160
-8*160 = -1280
Kerone
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May 17, 2018
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