Question

Sodium hydroxide (NaOH) and hydrochloric acid (HCl) react to form sodium chloride (NaCl) and water according to the equation:

NaOH + HCl → NaCl + H2O

What mass of water forms when 2.75 × 10–4 mol NaOH reacts completely?

2.75 × 10–4 mol NaOH = _______g H2O (fill in the blank)

Answer 1

0.00496

Step-by-step explanation:

e2020

Answer 2

Answer: The mass of
`H_2O` formed will be
`4.95* 10^(-3)` grams

Step-by-step explanation:

For the given reaction:

`NaOH+HCl\rightarrow NaCl+H_2O`

By Stoichiometry of the reaction:

1 mole of NaCl produces 1 mole of water molecule.

So,
`2.75* 10^(-4)mol` of NaCl will produce
`2.75* 10^(-4)mol` of
`H_2O`

To calculate the mass of water, we will use the equation used to calculate number of moles, which is:

`\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}`

Number of moles of
`H_2O=2.75* 10^(-4)` moles

Molar mass of water = 18 g/mol

Putting values in above equation, we get:

`2.75* 10^(-4)mol=\frac{\text{Given mass}}{18g/mol}\\\\\text{Given mass of water}=4.95* 10^(-3)g`

Hence, the mass of
`H_2O` formed will be
`4.95* 10^(-3)` grams