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Wat is the simplified expression for 3^-4 • 2^3 • 3^2 over 2^4 • 3^-3

2 Answers

6 votes
The answer is: "
(3)/(2)
" .
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(or, write as: "1½" ; or, "1.5").
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Step-by-step explanation:
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We are asked to simplify the given expression:
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(3^(-4)×2^(3)×3^(2) )/(2^(4)×3^(-3)) ;
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Note: In the "numerator" :
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2³ = 2 × 2 × 2 = 8 .

3² = 3 × 3 = 9 .
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Note: In the "denominator" :
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2⁴ = 2 × 2 × 2 × 2 = 16 .
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So, rewrite our expression; substituting "8" for "(2³)";
and substituting "9" for "(3²)" — [in the numerator] ;
and substituting: "16" for "(2⁴)" — [in the denominator] ;
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→ AS FOLLOWS:
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(3^(-4)×2^(3)×3^(2) )/(2^(4)×3^(-3)) ;

=
(3^(-4)×8×(9)/(16×3^(-3)) ;
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Since we have an "8" in the "numerator"; and a "16" in the "denominator" —respectively; and since both values, taken individually in the numerator—and taken individually in the denominator— are multiplied by other values as isolated numbers; we can "cancel out" the "8" in the "numerator" to a "1"; and change the "16" in the "denominator" to a "2" ; since:
"16÷8 = 2" ; and since "8÷8=1" ; that is: "8/16 = 1/2". We can then "eliminate" the "1" in the "numerator"; since in the numerator, there are other values that are multiplied by this "1" ; & any value multiplied by "1" is equal to that same value.
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So we can rewrite the expression, as follows:
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(3^(-4)×(9))/(2×3^(-3)) ;

Rearrange and rewrite as follows:
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(3^(-4)×(9))/(2×3^(-3))

=
\frac{(9) *{3^(-4)}{2×3^(-3)} ;
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Note the following properties of exponents:
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(
\frac{a} {b} =
( a^(n))/(b^(n)) ;
(b ≠ 0) ;
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(
a^(m) ) = a
a^((m*n))};
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a^(m) a^(n) = a^((m+n));

and especially
:


( a^(m))/( a^(n)) = a^((m-n)) ; (a \\eq 0) ;;

and especially:


a^(-n) = (1)/((a^(n) )) ; (a
\\eq 0);); If "n" is a positive integer; and if "a" is a non-zero real number.
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So; (3⁴) / (3³) = 3⁽⁽⁻⁻ ⁽⁻³⁾⁾ = 3⁽⁻⁴ ⁺ ³⁾ = 3⁻¹
=
(1)/((3^(1))) = (1)/(3) ; ;
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Rewrite the expression:
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\frac{(9) *{3^(-4)}{2×3^(-3)} ;

=
image ; or; write as: " 1 ½ " ; or, write as: " 1.5 ".
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User Dime
by
7.1k points
1 vote
(3^-4)(2^3)(3^2)
-----------------
(2^4)(3^-3)
I will keep this as simple as possible (for clarity). Any negative exponents should be switched from top to bottom and the negative sign removed from the exponent.

(3^3)(2^3)(3^2)
-----------------
(2^4)(3^4)

Add the like terms in the numerator

(3^5)(2^3)
----------
(2^4)(3^4)

Since we have powers of 3 and powers of 2 in the numerator and denominator we can add them together (just like when we reduce other fractions) For example, x^4/x => x^3, or x^1/x^6 => 1/x^5

3/2

Final answer 3/2.
User Parthiv
by
6.9k points
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