313,940 views
10 votes
10 votes
Select the two values of x that are roots of this equation.x2 - 5x + 3 = 0OI B. X-A. x. 5+ y27B. x-5-Ec. x. 5-797D. x 5 + 5O C.

User Jefry Jacky
by
2.6k points

1 Answer

9 votes
9 votes

SOLUTION:

To find the roots of this given equation, we either make use of completing the square method or formula method because it is obvious that equation is not factorisable.


\begin{gathered} x\text{ = }\frac{-b\text{ }\pm\text{ }\sqrt[]{b^2\text{ - 4ac}}}{2a} \\ \\ x^2\text{ - 5x + 3 = 0} \\ a\text{ = 1, b = -5 and c = 3} \\ x\text{ = }\frac{-(-5)\text{ }\pm\sqrt[]{(-5)^2\text{ - 4 (1) (3)}}}{2\text{ (1)}} \\ \\ x\text{ = }\frac{5\text{ }\pm\sqrt[]{25-12}}{2} \\ \\ x\text{ = }\frac{5\text{ }\pm\sqrt[]{13}}{2} \\ \\ x\text{ =}\frac{5+\sqrt[]{13}}{2}\text{ and x = }\frac{5\text{ - }\sqrt[]{13}}{2} \end{gathered}

The correct options are options B and D.

User Mediafreakch
by
2.7k points