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There are 12 balls numbered 1 through 12 placed in a bucket. What is the probability of reaching into the bucket and randomly drawing two balls numbered 9 and 3 without replacement, in that order? Express your answer as a fraction in lowest terms or a decimal rounded to the nearest millionth.

User JBeurer
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2 Answers

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27 votes

Final answer:

The probability of drawing two balls numbered 9 and 3 without replacement is 1/66 or approximately 0.015152.

Step-by-step explanation:

The probability of randomly drawing two balls numbered 9 and 3 without replacement, in that order, can be calculated by dividing the number of favorable outcomes by the total number of possible outcomes.

In this case, there is only 1 ball numbered 9 and 1 ball numbered 3, so the probability of drawing these two balls in the specific order is:

Probability = (Number of ways to draw 9 and 3) / (Total number of possible outcomes)

Probability = 1 / (12 choose 2) = 1/66 or approximately 0.015152

User Jeff Hardy
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Answer:

Step-by-step explanation:

User Dargaud
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