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How many combinations of 3 students can a teacher choose from 32 students? A. 96 B. 4960 C. 29,760 D. 32,768
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5 votes
How many combinations of 3 students can a teacher choose from 32 students?

A.
96


B.
4960


C.
29,760


D.
32,768

User Andrew Sasha
by
6.2k points

1 Answer

5 votes
The answer is: [B]: "4960" .
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Step-by-step explanation:
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32C3 = [(32!)] / [ 3! *(32-3)! ] ;

= [(32!)] / [ 3! *(29!) ]

= (32*31*30) / (1*2*3) = 29760 / 6 = 4960 .
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User Wxtry
by
5.3k points
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