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41 votes
41 votes
A 60-W light bulb consumes 60 W of electrical power. It radiates almost all of this power, some of it in the form of visible light and some of it in the form of heat. Find the intensity of the total radiated energy (light and heat) at a distance 3.7 m from the light bulb.\

User Chris Frisina
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1 Answer

22 votes
22 votes

Answer:

0.349W/m²

Step-by-step explanation:

We can use the intensity formula [ I = P/T ].

= P / 4πr²

= 60/4π(3.7)²

= 60/4(3.14)(13.69)

= 60/4(42.9866)

= 60/171.9464

≈ 0.349W/m²

Best of Luck!

User Jqgsninimo
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