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a total of 6 family members will appear in a portrait. If 3 of the family members may sit in the front row, how many combinations of family members may sit in the front row?
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a total of 6 family members will appear in a portrait. If 3 of the family members may sit in the front row, how many combinations of family members may sit in the front row?

User Huckleberry Carignan
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8.3k points

1 Answer

5 votes
Basically, it is asking in how many ways can you choose 3 people out of a set of six.

combinations = n! / (r! * (n-r)!)
combinations = 6! / 3! * 3!
combinations = 6 * 5 * 4 / 3!
combinations = 20

User JPetric
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7.9k points
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