Question

a parking lot is constructed in the shape of a parallelogram if the base is 200 in the height is 120 ft and a diagonal with its 140 what is the area of the parking lot

Answer 1

We can draw the following picture:

then, we can see that the parallelogram consists in 2 equal triangles:

The area of a triangle is

`A_T=(b\cdot h)/(2)`

By substituting the given values into the area formula, we get

`\begin{gathered} \\ A_T=(200\cdot120)/(2) \\ A_T=(24000)/(2) \\ A_T=12000ft^2 \end{gathered}`

Therefore, the area of the parallelogram is twice the area of one triangle:

`A_{\text{parallelogram}}=2\cdot A_T`

which gives:

`\begin{gathered} A_{\text{parallelogram}}=2\cdot12000 \\ A_{\text{parallelogram}}=24000ft^2 \end{gathered}`

that is, the answer is 24000 ft^2