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A region is bounded in the second quadrant by the curve y=ln(1-x), the line y=3, and the y-axis. Find the area of the region. Would the interval be 3 and 0 and would the equation be set up like 3-ln(1-x)
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Apr 21, 2018
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A region is bounded in the second quadrant by the curve y=ln(1-x), the line y=3, and the y-axis. Find the area of the region.
Would the interval be 3 and 0 and would the equation be set up like 3-ln(1-x) upper bound 3 and lower bound 0?
Mathematics
high-school
Anuj Teotia
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Anuj Teotia
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Yes that's right, the intervals would be 3 and 0, and 3-ln(1-x)
upper bound 3 and lower bound 0. Exactly.
Amir Sherafatian
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Apr 25, 2018
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Amir Sherafatian
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