Question

A party rental company has chairs and tables for rent. The total cost to rent 2 chairs and 5 tables is $43. The total cost to rent 8 chairs and 3 tables is $36. What is the cost to rent each chair and each table?

Answer 1

using using elimination.....you get the tables are $8 and the chairs are $1.5

Answer 2

Let's denote the cost of renting one chair as C and one table as T. The problem states that the total cost to rent 2 chairs and 5 tables is $43, and the total cost to rent 8 chairs and 3 tables is $36.

We can set up a system of two equations to represent the given information:

Equation 1: 2C+5T=43 Equation 2: 8C+3T=36

Now, we can use a method such as substitution or elimination to solve this system of equations. Let's use the elimination method.

Multiply Equation 1 by 4 to make the coefficients of C in both equations the same:

Equation 1 (after multiplication): 8C+20T=172 Equation 2: 8C+3T=36

Now, subtract Equation 2 from Equation 1 to eliminate C:

17T=136

Divide both sides by 17:

T=8

Now that we know T=8, substitute this value into Equation 1 to solve for C:

2C+5(8)=43

Solving for C, we find C=6.

Therefore, the cost to rent each chair is $6, and the cost to rent each table is $8.