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X+y=11, x.y=18 so what is the x^2 + y^2?

User Sadik
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2 Answers

2 votes
Another way to look at it

Solve xy = 18 and get y = (1/x)18

plug into other eq get

x + (1/x)18 = 11

multiply both sides by x get

x² -11x +18 = 0

find roots

x = 2 or 9

You can use the same method to find that y is either 2 or 9. You do not have enough information to know which is which so x² + y² is either 2² + 9² or 9² + 2²

in either case the answer is 85
User Godin
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7.8k points
2 votes
Let's begin with a basic formula

(x+y)^(2) = x^(2) + 2xy + y^(2)

so since we know the value of x + y and xy let's place those values inside the equation.

If xy=18, 2xy=36


11^(2)=x^(2) + 36 + y^(2)


121=x^(2)+y^(2)+36


85=x^(2) + y^(2)
User Wolfyuk
by
8.1k points

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