Question

Vector v has an initial point at (8, 4) and a terminal point at (−8, 10). What is -1/2 times vector v?

Answer 1

In order to find a vector multiplication by a scalar, we follow the rule:

`u\ast(n_1,n_2)_\Rightarrow(un_(1,)un_2)`

then, if we apply it to the vector v, we need to find the dimensions of the vector, for that we subtract the initial point from the terminal point,

`(-8-8,10-4)\Rightarrow(-16,6)`

then, multiply by the scalar -1/2,

`-(1)/(2)\ast(-16,6)\Rightarrow(8,-3)`

Answer:

`(8,-3)`