Question

If the perimeter is 22 inches and the area is 28 square inches. What are the dimensions.

Answer 1

P=2x+2y

P=2(x+y)

y=(P/2)-x

A=xy and using y from above we get:

A=(Px/2)-x^2 since A=28 and P=22

28=(22x/2)-x^2

28=11x-x^2

x^2-11x+28=0

(x-7)(x-4)

So the dimensions are 7 inches by 4 inches