Question

A quadratic equation of the form 0 = ax2 + bx + c has one real number solution. Which could be the equation?

Answer 1

0 = -2x^2 - 4x -2

C on edge

Answer 2

The equation showing this situation is
`D=b^2-4ac=0`

Explanation:

Given : A quadratic equation of the form
`ax^2 + bx + c=0` has one real number solution.

To find : Which could be the equation?

Solution :

A quadratic equation in form
`ax^2+bx+c=0` has a solution
`x=(-b\pm√(b^2-4ac))/(2a)` called a quadratic formula in which the roots are one real,two real or no real is determine by discriminant factor.

Discriminant is defined as to determine the number of roots in a quadratic equitation has following rules :

1) If
`D=b^2-4ac>0` there are two real roots.

2) If
`D=b^2-4ac=0` there are one real roots.

3) If
`D=b^2-4ac<0` there are no real roots.

According to question,

A quadratic equation of the form
`ax^2 + bx + c=0` has one real number solution.

So, The equation showing this situation is
`D=b^2-4ac=0`