Question

I need help to find the indicated operation:h(x)= x^2 +1g(x)= 3x+2Find (3h-g)(1)

Answer 1

In order to find (3h-g)(1), first let's find the function (3h-g)(x), that is, 3*h(x) - g(x):

`\begin{gathered} (3h-g)(x)=3h(x)-g(x) \\ =3(x^2+1)-(3x+2) \\ =3x^2+3-3x-2 \\ =3x^2-3x+1 \end{gathered}`

Now, let's evaluate it for x = 1:

`\begin{gathered} (3h-g)(1)=3\cdot(1)^2-3(1)+1 \\ =3\cdot1-3+1 \\ =3-3+1 \\ =1 \end{gathered}`

So the value of (3h-g)(1) is 1.