Question

What is the equation of the line that passes through (-3,-1) and has a slope of 2/5? Put your answer in slope-intercept form.

Really need the help thx :)

Answer 1

Slope-intercept form is y=mx+b where m=slope and b=y-intercept

We are told the slope is 2/5 so:

y=2x/5+b, using the point (-3-1) we can solve for b:

-1=2(-3)/5+b

-1=-6/5+b so

b=1/5 thus the line is:

y=(2x+1)/5

Answer 2

`\bf y-{{ y_1}}={{ m}}(x-{{ x_1}})\implies y-(-1)=\cfrac{2}{5}(x-(-3)) \\\\\\ y+1=\cfrac{2}{5}(x+3)\implies y+1=\cfrac{2}{5}x+\cfrac{6}{5}\implies y=\cfrac{2}{5}x+\cfrac{6}{5}-1 \\\\\\ \begin{array}{llll} y=&\cfrac{2}{5}x&+\cfrac{1}{5}\\ &\uparrow &\quad \uparrow \\ &slope&y-intercept \end{array}\impliedby \textit{slope-intercept form}`