Question

What is the molarity of a 0.250 L solution that contains 0.04 moles of CsBr?

Answer 1

Answer: the molarity of this solution is 0.16 M

Step-by-step explanation:

The question requires us to calculate the molarity of a solution which contains 0.04 moles of CsBr and a volume of 0.250 L.

The molarity of a solution can be calculated using the following equation:

`M=(n)/(V)`

where M corresponds to the molarity (or molar concentration, in mol/L), n corresponds to the number of moles of solute (in mol) and V is the volume of the solution (in L).

Applying the values of number of moles (0.04 mol of CsBr) and volume of solution (0.250 L) given by the question to the equation above, we'll have:

`M=(0.04mol)/(0.250L)=0.16mol/L=0.16M`

Therefore, the molarity of this solution is 0.16 M.