Question

*J has coordinates of (10,-2) and n has coordinates of (-4,6) find the midpoint of jn

Answer 1

The he coordinates of midpoint of JN are (3,2).

Explanation:

The coordinates of J are (10,-2) and the coordinates of N are (-4,6).

The midpoint formula:

`m=((x_1+x_2)/(2),(y_1+y_2)/(2))`

The midpoints of JN is

`m=((10+(-4))/(2),(-2+6)/(2))`

`m=((6)/(2),(4)/(2))`

`m=(3,2)`

Therefore the coordinates of midpoint of JN are (3,2).

Answer 2

The midpoint of the line JN is calculated by getting the sum of the coordinates and dividing by 2.
x - coordinate = (10 + -4) / 2 = 3
y - coordinate = (-2 + 6) / 2 = 2

Therefore, the midpoint of line JN is equal to (3, 2).