Question

Find the distance between (0,-1) and (2,3)

Answer 1

`\sqrt{(2-0) ^(2) + (3-(-1)){2}` =4.47

Answer 2

The distance between two points if found using the Pythagorean Theorem...

d^2=(dx)^2+(dy)^2

d^2=(2-0)^2+(3--1)^2

d^2=2^2+4^2

d^2=4+16

d^2=20

d=√20 units

d≈4.47 units (to nearest hundredth of a unit)