Question

The first steps in writing f(x) = 4x2 + 48x + 10 in vertex form are shown. f(x) = 4(x2 + 12x) + 10 = 36 What is the function written in vertex form? f(x) = 4(x + 6)2 + 10 f(x) = 4(x + 6)2 – 26 f(x) = 4(x + 6)2 – 134 f(x) = 4(x + 6)2 + 154

Answer 1

c

Explanation:

edge

Answer 2

we have

`f(x)=4x^(2)+48x+10`

Group terms that contain the same variable, and move the constant to the opposite side of the equation

`f(x)-10=4x^(2)+48x`

Factor the leading coefficient

`f(x)-10=4(x^(2)+12x)`

Complete the square. Remember to balance the equation by adding the same constants to each side

`f(x)-10+144=4(x^(2)+12x+36)`

`f(x)+134=4(x^(2)+12x+36)`

Rewrite as perfect squares

`f(x)+134=4(x+6)^(2)`

`f(x)=4(x+6)^(2)-134` ------> equation in vertex form

therefore

the answer is

`f(x)=4(x+6)^(2)-134`