Question

A bag contains 2 red,5 blue,6 yellow, and 3 green crayons. What is the probability of selecting a red crayon, then without replacing it selecting an odd number that is (red, then green)

A.0
B.0.25
C.01
D.0.025

Answer 1

Answer: D.0.025

Explanation:

Given: A bag contains 2 red,5 blue,6 yellow, and 3 green crayons.

Total crayons: 2+5+6+3=16

Probability of getting red crayon=
`\frac{\text{Number of red crayons}}{\text{Total}}`

`=(2)/(16)=\frac18`

Without replacement, the probability of getting green crayon =
`\frac{\text{Number of green crayons}}{\text{Total}-1}`

`=(3)/(15)=\frac15`

Required probability P(red then green)=
`\frac18*\frac15=\frac1{40}=0.025`

Hence, correct option is D.0.025