Question

Jason tossed a fair coin 3 times. What is the probability of getting a head and two tails in any order?

3 over 8
4 over 8
5 over 8
6 over 8

Answer 1

3 0ver 8 (a)

because:

(h =heads)-(t=tails)

(hhh), (ttt), (hht), (hth), (thh), (htt), (tth), (tht)

the total number of options is 8 and 3 of them give you

1 head and 2 tails

so you take the 3 options and put it over 8 so 3/8 (A)

hope this helps

Answer 2

Answer: 3 over 8

Explanation:

Given: Jason tossed a fair coin 3 times. What is

Sample space : {HHH, TTT, HHT, TTH, THT, HTH, THH, HTT}

Number of possible outcomes = 8

The favorable outcomes of getting a head and two tails in any order (HTT,THT,TTH)=3

Since, Probability=
`\frac{\text{favorable outcomes}}{\text{Total outcomes}}`

Hence, the probability of getting a head and two tails in any order=
`(3)/(8)`