Question

Two pools are being filled with water. To start, the first pool contains 612 liters of water and the second pool is empty. Water is being added to the first pool at a rate of 15.25 liters per minute. Water is being added to the second pool at a rate of 40.75 liters per minute.After how many minutes will the two pools have the same amount of water?How much water will be in each pool when they have the same amount?

Answer 1

Given:

The number of litters in the first pool = 612 liters.

The rate of water added to the first pool = 15.25 litters per minute.

The rate of water added to the second pool = 40.75 litters per minute.

Aim:

We need to find the number of minutes when the two pools have the same amount of water and the number of litter of water in each pool when they have the same amount.

Step-by-step explanation:

Let t be the number of minutes.

The water in the first pool after t minutes is

`=612+15.25t`

The water in the second pool after t minutes is

`=40.75t`

The two pools have the same amount of water, the equation for this model is

`612+15.25t=40.75t`

Solve for t.

`40.75t-15.25t=612`

`25.5t=612`

`t=(612)/(25.5)`

`t=24`

After 24 minutes, the two pools have the same amount of water

Substitute t=24 in the 40.75t.

`40.75*24=978`

978 litters in the each pool when they have the same amount.

Final answer:

After 24 minutes, the two pools have the same amount of water

978 litters in the each pool when they have the same amount.